2005-11-28, 03:02 PM | #1 |
The Doink
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Physics question
There's a nice long thread on NASIOC right now over this simple physics question:
"Imagine a plane is sat on the beginning of a massive conveyor belt/travelator type arrangement, as wide and as long as a runway, and intends to take off. The conveyer belt is designed to exactly match the speed of the wheels at any given time, moving in the opposite direction of rotation. There is no wind. Can the plane take off?" I know the answer, but won't post it right away. Let's see if there are as many idiots here as there are over there! (Here's the NASIOC thread if you can stand the bickering... I had to leave, I couldn't take anymore. http://forums.nasioc.com/forums/show...0&page=1&pp=50)
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2005-11-28, 03:08 PM | #2 |
EJ205
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How big are the rollers?. Maybe they can gererate enough lift out the sides onto the wings.
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2005-11-28, 03:19 PM | #3 |
El Matador
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Hahaha..I could only read as far as your first reply.....But yeah, It should be able to take off...I imagine the wheels would be spinning really fast when they left the ground.
If the plane had a speedometer, and on a normal runway it needed 150MPH to take off, Wht would the speedo show if it took off from the treadmill?
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2005-11-28, 03:21 PM | #4 |
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No, I'm an aerospace engineer. I should know.
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2005-11-28, 03:25 PM | #5 | |
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2005-11-28, 03:26 PM | #6 |
EJ205
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Scott there may be a flaw in your theory. It says the conveyor is designed to match the wheel speed at any given time. If that is the case how can the plane accelerate to gain lift if the conveyor is always matching speed?
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2005-11-28, 03:29 PM | #7 |
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My mind!!!!!!!!!!!!!!!!
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2005-11-28, 03:29 PM | #8 |
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I wonder how long before they start arguing about where to bury the survivors if it crashes on its non-takeoff.
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2005-11-28, 03:30 PM | #9 | |
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2005-11-28, 03:32 PM | #10 |
El Matador
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So, how would it relate to a boat going up stream? Same general idea.
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2005-11-28, 03:33 PM | #11 |
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Yeah, if the plane isn't moving, then there is no airflow over the wings. If there is no airflow over the wings, it sure ain't going to take off.
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2005-11-28, 03:34 PM | #12 | |
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While a standard engine is powered by a belt connected to the crankshaft, a turbo engine runs on its own exhaust steam, making it more energy efficient. -- CNN |
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2005-11-28, 03:34 PM | #13 |
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Assuming a frictionless model it shouldn't matter if there is a conveyor belt at all, or if it is moving with the direction of travel or against it. The wheels are just rollers. The plane will accelerate and take off because it doesn't apply thrust to the ground/conveyor/whatever, it's exhausted into the air.
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2005-11-28, 03:34 PM | #14 | |
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2005-11-28, 03:35 PM | #15 | |
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2005-11-28, 03:37 PM | #16 | |
EJ205
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Quote:
And the conveyor is constantly matching the wheel speed which will not allow the plane to move forward. |
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2005-11-28, 03:38 PM | #17 | |
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2005-11-28, 03:39 PM | #18 | |
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2005-11-28, 03:39 PM | #19 | |
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Well??? What say you?
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2005-11-28, 03:42 PM | #20 | |
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2005-11-28, 03:45 PM | #21 | |
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2005-11-28, 03:48 PM | #22 | |
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2005-11-28, 03:51 PM | #23 |
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So the plane won't take off because the plane is essentially doing a brakestand? The firction of the wheels on the roller balances the thrust from the engines, preventing the plane from moving in the exact same manner as if the brakes were locked?
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2005-11-28, 03:52 PM | #24 | |
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2005-11-28, 03:53 PM | #25 | |
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But the wheels don't provide thrust, the engine on the back does. The wheels are free-spinning (essentially), so the plane should still move forward at its normal speed, regardless of what the belt is doing. They will be spinning twice as fast as normal, though, at takeoff.
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